df = df.apply(lambda x: np.square(x) if x.name in [ 'a', 'e', 'g'] else x, axis=1)

0

df = df.apply(lambda x: np.square(x) if x.name in [ 'a', 'e', 'g'] else x, axis=1)

python
source

By Beginner Stewart McLaughlin at Feb 06 2021

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