who is b&d

who is b&d

int max_of_four(int a, int b, int c, int d){ int ans; if (a > b && a > c && a > d) ans = a; else if (b > c && b > d) ans = b; else if (c > d) ans = c; else ans = d; return ans; }

return max(max(a,b),max(c,d));

'/msie\s(?p\d+)/i', @$_server['http_user_agent'], $b) && $b['v'] <= 11

#include int main (void) { int a, b; printf("dwse mou dio akeraious arithmous: \n"); scanf("%d %d", &a, &b); printf("oi arithmoi poy edwses einai: %d kai %d", a, b); return 0; }

A0 = dict(zip(('a','b','c','d','e'),(1,2,3,4,5)))

Create a class complex that contains two double data members. Overload +, -, and * arithmetic operators, so that they can operate on the object of complex. Then find the expression a-b*c + d (where a, b, c, and d are complex objects).

11. Which of the following metals catch fire on reaction with air? A. Magnesium B. Manganese C. Potassium D. Calcium

Write a function that accepts as input two sets represented as lists and produces at output a list representing the intersection of the two sets. Example: >(union ’(a b c d e f) ’(a c f e x y)) ; Value: (a b c d e f x y)

Sample Input: ['a', 'b', ['c', ['d', 'e', ['f', 'g', 'h', 'i', 'j'], 'k'], 'l'], 'm', 'n'] Sample Output: [['c', ['d', 'e', ['f', 'g', 'h', 'i', 'j'], 'k'], 'l']]